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Question

Prove that sec2(tan12)+csc2(cot13)=15.

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Solution

sec2(tan12)+cosec2(cot13)=15
LHS :
sec2(tan12)+cosec2(cot13)
{sec(tan12)}2+{cosec(cot13)}2
or
[sec(sec151)]2+[cosec(cosec110)]2
=(5)2+(10)2
=5+10
=15
= RHS
Hence proved

1121156_1140095_ans_032fcd4efbe146669e5f4ecc1043401d.jpeg

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