Prove that (sin x -sin3x -sin5x)/(cosx-cos3x-cos5x)=-tan3x

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\frac{sin x - sin 3 x + sin 5 x - sin 7 x}{cos x - cos 3 x - cos 5 x + cos 7 x} = cot 2 x

\frac{sin 5 x + sin 3 x}{cos 5 x + cos 3 x} = tan 4 x

\frac{s i n x - s i n 3 x + s i n 5 x - s i n 7 x}{c o s x - c o s 3 x - c o s 5 x + c o s 7 x} = c o t 2 x

\frac{sin 5 x + sin 3 x}{cos 5 x + cos 3 x} =

\frac{sin 5 x - sin 3 x}{cos 5 x + cos 3 x}

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