Range of Trigonometric Ratios from 0 to 90 Degrees
Prove that ta...
Question
Prove that
tan2 A sec2B - sec2 A tan2 B = tan2 A - tan2 B
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Solution
We know 1+tan²x=sec²x therefore LHS of the equation becomes, tan²Asec²B-sec²Atan²B i.e tan²A(1+tan²B)-(1+tan²A)tan²B i.e tan²A+tan²Atan²B-tan²B-tan²Atan²B