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Question

Prove that

tan2 A sec2B - sec2 A tan2 B = tan2 A - tan2 B

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Solution

We know 1+tan²x=sec²x
therefore LHS of the equation becomes,
tan²Asec²B-sec²Atan²B
i.e tan²A(1+tan²B)-(1+tan²A)tan²B
i.e tan²A+tan²Atan²B-tan²B-tan²Atan²B
i.e tan²A-tan²B
hence LHS=RHS

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