wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Prove that

tan2 A sec2B - sec2 A tan2 B = tan2 A - tan2 B

Open in App
Solution

We know 1+tan²x=sec²x
therefore LHS of the equation becomes,
tan²Asec²B-sec²Atan²B
i.e tan²A(1+tan²B)-(1+tan²A)tan²B
i.e tan²A+tan²Atan²B-tan²B-tan²Atan²B
i.e tan²A-tan²B
hence LHS=RHS

​​​​​

flag
Suggest Corrections
thumbs-up
12
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Range of Trigonometric Ratios from 0 to 90
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon