The given function f( x ) is defined as,
f( x )= x 3 −3 x 2 +3x−100
The derivative of the function f( x ) is given as,
f ′ ( x )= df( x ) dx = d( x 3 −3 x 2 +3x−100 ) dx =3 x 2 −6x+3 =3 ( x−1 ) 2
For the given interval x∈R,
3 ( x−1 ) 2 >0
Hence, f ′ ( x )>0.
As f ′ ( x )>0, then the given function f( x ) is increasing in R.
Prove that the function given by is increasing in R.