Question

Q. If $11x^2-59xy+51y^2=0$ what is x:y?

• A. 3:1
• B. 11:17
• C. 11:17 or 3:1
• D. 17:11 or 3:1
• E. None of these

Answer 1

The correct option is D 17:11 or 3:1

$11x^2-59xy+51y^2=011x^2-33xy-17xy+51y^2=011x(x-3y)-17y(x-3y)=0(11x-17y)=0,(x-3y)=0\frac{x}{y}=\frac{17}{11},\frac{x}{y}=3x:y=17:11orx:y=3:1$