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Byju's Answer
Standard XII
Chemistry
Heat of Formation
Q. the enthal...
Question
Q. the enthalpy of solution of NaCl is 4 KJ mol^{-1} and its enthalpy of hydration of ions is -784KJ mol^{-1} what will be the lattice enthalpy of NaCl.
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Q.
The change in enthalpy for hydration of ( i ) the chloride ion ; ( ii ) the iodide ion are :
Given :
* enthalpy change of solution of NaCl(s)
=
−
2
kJ / mol.
* enthalpy change of solution of NaI(s)
=
+
2
kJ / mol.
* enthalpy change of hydration of
N
a
+
(
g
)
=
−
390
kJ / mol.
* lattice enthalpy of NaCl
=
−
772
kJ / mol.
* lattice enthalpy of NaI
=
−
699
kJ / mol.
Q.
The enthalpy of dissolution(or solution) of sodium chloride is
4
k
J
m
o
l
−
1
and its enthalpy of hydration of ions is
−
784
k
J
m
o
l
−
1
. What will be the lattice enthalpy of sodium chloride?
Q.
The lattice enthalpy of solid
N
a
C
l
is
772
k
J
m
o
l
−
1
and enthalpy of solution is
2
k
J
m
o
l
−
1
. If the hydration enthalpy of
N
a
+
and
C
l
−
ions are in the ratio of
3
:
2.5
, what is the enthalpy of hydration of chloride ion?
Q.
The lattice energy of
N
a
C
l
(
s
)
is
−
790
k
J
.
m
o
l
−
1
and enthalpy of hydration is
−
785
k
J
.
m
o
l
−
1
. Calculate the enthalpy of the solution of
N
a
C
l
(
s
)
.
Q.
Calculate the hydration enthalpy of ions for
N
a
C
l
(
s
)
from the following data.
Δ
l
a
t
t
i
c
e
H
=
+
788
k
J
m
o
l
−
1
Δ
s
o
l
H
=
+
4
k
J
m
o
l
−
1
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