Question 2(ii)

Factorise
$63 a^{2} - 112 b^{2}$

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Solution

$63 a^{2} - 112 b^{2} = 7 (9 a^{2} - 16 b^{2}) = 7 [(3 a)^{2} - (4 b)^{2}] = 7 (3 a + 4 b) (3 a - 4 b) [a^{2} - b^{2} = (a - b) (a + b)]$

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Factorise

$63 a^{2} - 112 b^{2}$

Factorise :

$63 a^{2} - 112 b^{2}$

63 a^{2} - 112 b^{2}

63 a^{2} - 112 b^{2}

63 a^{2} - 112 b^{2}

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