3(5z−7)−2(9z−11)=4(8z−13)−17⇒15z−21−18z+22=32Z−52−17
⇒−3z+1=32z−69⇒−3z−32z=−69−1
⇒−35z=−70
z=2
To check:
3(5z−7)−2(9z−11)=4(8z−13)−17
⇒3(5×2−7)−2(9×2−11)=4(8×2−13)−17
⇒3(10−7)−2(18−11)=4(16−13)−17
⇒3×3−2×7=4×3−17⇒9−14=12−17
⇒−5=−5
⇒L.H.S.=R.H.S
Therefore, it is correct.