Question

Ranjan spins a spinner $25$ times, and makes a list for the number of times (frequency) he gets the specific colors in the table below.

$\text{Color}$	$\text{Frequency}$
Yellow	$6$
Purple	$5$
Orange	$3$
Red	$4$
Green	$7$

What is the experimental probability of getting orange color in Ranjan's ${26}^{\text{th}}$ spinning?

• A. $\frac{3}{25}$
• B. $\frac{3}{22}$
• C. $\frac{22}{25}$
• D. None of the above

Answer 1

The correct option is A $\frac{3}{25}$

Below is the given table:

$\text{Color}$	$\text{Frequency}$
Yellow	$6$
Purple	$5$
Orange	$3$
Red	$4$
Green	$7$

Total number of spinning= $25$
Number of times orange appears= $3$ (from the above table)

$\therefore \text{Probability of getting orange}=$
$\frac{\text{Number of times orange appears}}{\text{Total number of spinning}}=\frac{3}{25}$

Hence, the experimental probability of landing orange in Ranjan's ${26}^{\text{th}}$ spinning is $\frac{3}{25}$.