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Measurement of Volume

Reaction betw...

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Reaction between N2 and O2 takes place as follows: 4N2 (g) + O2 (g) <-----> 2N2O (g) If a mixture of 0.482 mol N2 and 0.933 mol O2 is placed in a 10L reaction vessel and allowed to form N2O at a temperature for which KC=2.0 INTO ( 10 TO THE POWER -37 ), determine the concentration of equilibrium mixture.

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Reaction between N₂ and O₂ takes place as follows:

If a mixture of 0.482 mol of N₂ and 0.933 mol of O₂ is placed in a 10 L reaction vessel and allowed to form N₂O at a temperature for which K_c = 2.0 × 10^–37, determine the composition of equilibrium mixture.

Reaction between $N_{2}$ and $O_{2}$ takes place as follows:
$2 N_{2} (g) + O_{2} (g) \leftrightarrow 2 N_{2} O (g)$
If a mixture of 0.482 mol of $N_{2}$ and 0.933 mol of $O_{2}$ is placed in a 10 L reaction vessel and allowed to form $N_{2} O$ at a temperature for which $K_{c} = 2.0 \times 10^{- 37}$ , determine the composition of equilibrium mixture.

Q. If a mixture of 0.482 mol

N_{2}

and 0.933 mol of

O_{2}

is placed in a 10 L reaction vessel and allowed to form

N_{2} O

at a temperature for which

K_{C} = 2.0 \times 10^{- 37}

. The composition of equilibrium mixture are :

Q. Reaction between nitrogen and oxygen takes place as follows:

{2 N}_{2} (g) + O_{2} (g) ⇌ {2 N}_{2} O (g)

If a mixture of

0.482

N_{2}

0.933

N_{2}

is placed in a reaction in a reaction vessel of volume

10 L

and allowed to form

N_{2} O

at a temperature for which

K_{c} = 2.0 \times 10^{- 37}

. Determine the composition of the equilibrium mixture.

Q. Reaction between Nitrogen and Oxygen takes place as follows:-

2 N_{2} (g) + O_{2} (g) ⇌ 2 N_{2} O (g)

If a mixture of

0.482 m o l

N_{2}

0.933 m o l

O_{2}

is placed in a reaction vessel of volume

10 L

and allowed to form

N_{2} O

at a temperature for which

K e = 2.0 \times 10^{- 37}

, determine the composition of the equilibrium mixture.

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