Question

Reduce the following to their lowest terms.

(a) $\frac{16}{40}$

(b) $\frac{36}{72}$

(c) $\frac{45}{63}$

Answer 1

(a) $\frac{16}{40}=\frac{16÷8}{40÷5}=\frac{2}{5}$

(b) $\frac{36}{72}=\frac{36÷4}{72÷4}=\frac{9÷9}{18÷9}=\frac{1}{2}$

(c) $\frac{45}{63}=\frac{45÷9}{63÷9}=\frac{5}{7}$