1
Question
Represent √7 on number line.
Represent √7 on number line.
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Solution
1) First draw OB=2cm, BC=1cm. Draw right angled triangle using the values.It's hypotenuse will be √5.[since √(2²+1²)=√5]
2)This √5 can be marked on number line using compus.
3)Use this √5 as base and 1 as adjuscent and draw right angled triangle. It's hypotenuse will be √6
4)Use this √6 as base and 1 as adjuscent side of a right angled triangle. It's hypotunues will be √7
Take this last hypotunues length and mark the same length from 0 on number line. That gives √7
1) First draw OB=2cm, BC=1cm. Draw right angled triangle using the values.It's hypotenuse will be √5.[since √(2²+1²)=√5]
2)This √5 can be marked on number line using compus.
3)Use this √5 as base and 1 as adjuscent and draw right angled triangle. It's hypotenuse will be √6
4)Use this √6 as base and 1 as adjuscent side of a right angled triangle. It's hypotunues will be √7
Take this last hypotunues length and mark the same length from 0 on number line. That gives √7
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