Show that (a−b)×(a+b)=2(a×b)
Given that (a−b)×(a+b)=2(a×b) LHS =(a−b)×(a+b)=a×a+a×b−b×a−b×b=0+a×b+a×b−0 [∵a×a=0 and a×b=−b×a] =2(a×b)= RHS Hence proved.