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To prove: √3+√5 is irrational
To prove it let us assume it to be a rational number
Rational numbers are the ones which can be expressed in p/q form where p,q are integers and q isn't equal to 0
√3+√5=p/q
√3=(p/q)-√5
Squatting on both sides
3=p²/q²-(2√5p)/q+5
(2√5p)/q=5-3-p²/q²
2√5p/q=(2q²-p²)/q²
√5=(2q²-p²)/q²*q/2p
√5=(2q²-p²)/2pq
As p and q are integers RHS is rational
As RHS is rational LHS is also rational i.e √5 is rational
But this contradicts the fact that √5 is irrational
This contradiction arose because of our false assumption
So √3+√5 is irrational