Question

Shown in figure, a conical container of half-apex angle ${37}^0$ filled with certain quantities of kerosene and water. The force exerted by the water on the kerosene is approximately. (Take atmospheric pressure = ${10}^5$ Pa)

• A. 3 x ${10}^7$ N
• B. 4 x ${10}^7$ N
• C. 2 x ${10}^7$ N
• D. 5 x ${10}^7$ N

Answer 1

The correct option is C 2 x ${10}^7$ N

$P\text{at layer}=$

${10}^5+(0.8\times {10}^3\times 10)$

$=1.8\times {10}^5$

Area $=\pi r^2$

$r=6m$

(because half

apex angle $={37}^{\circ }$.

$F=$ Pat layer $\times$ Area

$F=2\cdot 03\times {10}^{7}N$

Correct option is (C)