223.215Sine we know that
xn.xm=x(m+n)
223.215=223+15
Let's Solve the power as we have addition of unlike frcations
23+15
So, first find the lcm of 3 and 5, which would be 15
=2×5+1×315
=10+315
=1315
Therefore, 223+15=21315
or we can say
223.215=21315