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Question

Simplify:
223.215

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Solution

223.215
Sine we know that
xn.xm=x(m+n)
223.215=223+15

Let's Solve the power as we have addition of unlike frcations

23+15
So, first find the lcm of 3 and 5, which would be 15
=2×5+1×315

=10+315

=1315

Therefore, 223+15=21315
or we can say
223.215=21315

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