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Question

Simplify: (2a+3b)3(2a3b)3

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Solution

(2a+3b)3=(2a)3+(3b)3+3(2a)(3b)(2a+3b)
Using, (a+b)3=a3+b3+3ab(a+b)
=8a3+27b3+18ab(2a+3b)
=8a3+27b3+36a2b+54ab2 .........(i)
(2a3b)3=(2a)3(3b)33(2a)(3b)(2a3b)
Using, (ab)3=a3b33ab(ab)
=8a327b318ab(2a3b)
=8a327b336a2b+54ab2......(ii)
Subtracting (i) from (ii) we get,
(2a+3b)3(2a3b)3=8a3+27b3+36a2b+54ab2(8a327b336a2b+54ab2)
=8a3+27b3+36a2b+54ab28a3+27b3+36a2b54ab2
=54b3+72a2b

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