We know that (a + b)2= a2 + 2ab + b2
and (a − b)2 = a2- 2ab + b2 (1 mark)
(2x + 5)2= (2x)2 + 2 × 2x × 5 + 52
= 4x2 + 20x +25 (0.5 mark)
(2x − 5)2= (2x)2- 2 × 2x × 5 + 52
= 4x2- 20x + 25 (0.5 mark)
Therefore, (2x + 5)2 – (2x − 5)2
= (4x2+ 20x + 25) - (4x2- 20x + 25)
= (4x2+ 20x + 25 - 4x2+ 20x - 25)
=40x (1 mark)