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Question

Simplify: (3xy2ab)3(3xy+2ab)3

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Solution

(3xy2ab)3(3xy+2ab)3
Here, A = 3xy - 2ab and B = 3xy + 2ab
(3xy2ab)3(3xy+2ab)3
=[(3xy2ab)(3xy+2ab)][(3xy2ab)2+(3xy2ab)(3xy+2ab)+(3xy+2ab)2]
...[A3B3=(AB)(A2+AB+B2)]
=(3xy2ab3xy2ab)[(9x2y212xyab+4a2b2)+(9x2y24a2b2)+(9x2y2+12xyab+4a2b2)]
=(4ab)(9x2y2+9x2y2+9x2y212xyab+12xyab+4a2b24a2b2+4a2b2)
=(4ab)(27 xy2+4a2b2)
=108x2y2ab16a3b3

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