CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Simplify:
(i) (−2) × (−3)3
(ii) (−3)2 × (−5)3
(iii) (−2)5 × (−10)2

Open in App
Solution

We know that if 'a' is natural number, then
(−a)even number = Positive number
(−a)odd number = Negative number

We have

(i) (−2) × (−3)3 = ( −2 )(−27) = 54 [since (−3)3 = −3 ×−3 × − 3 = −27]
(ii) (−3)2 × ( −5)3 = 9 (−125) = −1125 [ since (−3)2 = −3 ×− 3 = 9 and (−5 )3 = −5 ×−5 × − 5 = −125]
(iii) ( −2)5 × (−10)2 = −32 × 100 = −3200 [ since (−2)5= −2 ×−2 × −2 ×−2 ×−2 = −32 and (−10)2 = −10 ×− 10 = 100]

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Multiplication of Integers_tackle
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon