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Question

Simplify:
(c0+c1c0)(c1+c2c1)(c2+c3c2).....(cn1+cncn1)

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Solution

We have,

(C0+C1C0)(C1+C2C1)(C2+C3C2)(C3+C4C3)..........(Cn1+CnCn1)

(1+C1C0)(1+C2C1)(1+C3C2)..........(1+CnCn1)

(1+n1)(1+n(n1)n2!)..................(1+1n)

(1+n1)(1+n1)(1+n1).................(1+n1)

(1+n)nn!

Hence, this is the answer.


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