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Question

Sin​​​​2​​​24° - Sin​​​​2​​​6°

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Solution

sin2A - sin2B = sin(A-B)sin(A+B)

taking LHS

sin224 - sin26=

sin18sin30=(sin18)/2

sin18 = (51/2-1)/4

So sin^24 -sin^6 =

(5^1/2 -1)/8


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