Solution set of x-1x-22x-4-x-2x-3- 0 is -

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Real Valued Functions

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Solution set of $\frac{(x - 1) (x - 2)^{2} (x - 4)}{(x + 2) (x - 3)} \geq 0$ is :

$(- \infty, - 4) \cup {2} \cup (3, \infty)$

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$(- 4, 2] \cup [1, 2] \cup (3, \infty)$

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$(- \infty, - 4) \cup {2} \cup (3, \infty)$

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