Solve: 0.5(5y−7)−2(9y−11)=0.25(8y−13)−534 [4 MARKS]
Concept: 1 Mark Application: 3 Marks 0.5(5y−7)−2(9y−11)=0.25(8y−13)−534 (5y−7)2−2(9y−11)=(8y−66)4 10y–14−72y+88=8y–66 −62y+74=8y−66 −70y=−140 y=2