The correct option is C 9 11 + ( 6) + 3 ( 5) = 11 6 + 3 + (additive inverse of 5) = 11 6 + 3 + 5 = (11 + 6) + 3 + 5 = (17) + 8 = 17 + 8 Here, we f ...

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Byju's Answer

Standard VI

Mathematics

Subtraction of Integers Using Additive Inverse

Solve :-11+-6...

Question

Solve : -11 + (-6) + 3 - (-5)

-9

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-19

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-10

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Solution

The correct option is A -9
-11 + (-6) + 3 - (-5)
= -11 - 6 + 3 + (additive inverse of -5)
= -11 - 6 + 3 + 5
= -(11 + 6) + 3 + 5
= -(17) + 8
= -17 + 8
Here, we form pair of negative and positive integers,
= -9 - 8 + 8 ( $∵$ -17 = -9 - 8)
= -9

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Similar questions

Q. Solve

\frac{- 5}{6} + \frac{3}{11}

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x + 7 - \frac{8 x}{3} = \frac{11}{6} - \frac{5 x}{8}

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Q. Solve:

2+5=12.
3+6=21.
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Solve :

(i)

4 \times \frac{1}{3}

(ii)

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(iii)

11 \times \frac{4}{7}

(iv)

20 \times \frac{4}{5}

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Solve : -11 + (-6) + 3 - (-5)

The correct option is A -9-11 + (-6) + 3 - (-5) = -11 - 6 + 3 + (additive inverse of -5) = -11 - 6 + 3 + 5 = -(11 + 6) + 3 + 5 = -(17) + 8 = -17 + 8 Here, we form pair of negative and positive integers, = -9 - 8 + 8 (∵ -17 = -9 - 8) = -9

The correct option is A -9
-11 + (-6) + 3 - (-5)
= -11 - 6 + 3 + (additive inverse of -5)
= -11 - 6 + 3 + 5
= -(11 + 6) + 3 + 5
= -(17) + 8
= -17 + 8
Here, we form pair of negative and positive integers,
= -9 - 8 + 8 ( $∵$ -17 = -9 - 8)
= -9