Solve : 15−2(2x−1)<15,x ϵ Z
15−2(2x−1)<15,x ϵ Z
⇒15−2(2x−1)<15,x ϵ Z⇒15−4x+2<15⇒17−4x<15⇒−4x<15−17⇒−4x<−2⇒−4−4x>−2−4=12 (Dividing by −4)∴x=1,2,3,4,5,....
∴ Solution set = {1,2,3,4,5,,.....}