Solve:

168 - 142 =

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Solution

The correct option is C 26

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Similar questions

lim x \to \infty [(1 - \frac{1}{2^{2}}) (1 - \frac{1}{3^{2}}) (1 - \frac{1}{4^{2}}) . . . (1 - \frac{1}{n^{2}})] =

x^{9} i n (x -^{21} C_{0}) (x -^{21} C_{1}) (x -^{21} C_{2}) . . . . . . (x -^{21} C_{10})

11^{2} + 8^{2} + 3^{2} = 19^{2}

12^{2} + 2^{2} + 10^{2} = 14^{2}

14^{2} + 7^{2}

48 : 122 :: 168 : ?

- (14)^{2} + 16^{2} - (- 1)^{2}

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