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Question

Solve 2x4+x311x2+x+2=0

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Solution

Solution:
2x4+x311x+x+2=0
or, 2x44x3+5x310x2x2+2xx+2=0
or, 2x3(x2)+5x2(x2)x(x2)1(x2)=0
or, (x2)(2x3+5x2x1)=0
or, (x2)(2x3x2+6x23x+2x1)=0
or, (x2){x2(2x1)+3x(2x1+1(2x1))}=0
or, (x2)(2x1)(x2+3x+1)=0
Now, x2+3x+1=0
or, x=3±942=3±52
or, (x2)(2x1)(x3+52)(x352)=0
Roots of given equation are 2,12,3+52 and 352.

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