Solve:- 4x−2−2x+1=0
-5
6
5
-6
Given,
4x−2−2x+1=0
⇒ 4x−2=2x+1
⇒ (22)x−2=2x+1
⇒ 22x−4=2x+1 [∵(am)n = amn]
Since the bases are equal, exponents must also be equal.
⇒2x−4=x+1
⇒ x=5
Cube root of (-2)3 x (-3)3 is:
Solve for x
x2−3x−10=0
2x2 - 11x + 15 when factorised gives _________.
Solve for x: 3x−5=13