Question

Solve:
$4x+\frac{6}{y}=15$
$6x-\frac{8}{y}=14$

• A. $x=-3,y=2$
• B. $x=2,y=3$
• C. $x=3,y=-2$
• D. $x=3,y=2$

Answer 1

The correct option is D $x=3,y=2$

Given: $4x+\frac{6}{y}=\mathrm{15......}\left(1\right)$

$6x-\frac{8}{y}=\mathrm{14......}\left(2\right)$

Multiplying equation (1) by 4 and equation (2) by 3 and then adding them,

$16x+\frac{24}{y}=60$

$\underset{–}{18x-\frac{24}{y}=42}$

$34x=102\Rightarrow x=3$

Now putting the value of x in equation (1)

$4\times 3+\frac{6}{y}=15\Rightarrow \frac{6}{y}=15-12\Rightarrow \frac{6}{y}=3\Rightarrow y=\frac{6}{3}=2$