Question

Solve: $x(x+5)=x^2+x+32$

Answer 1

Step: Find the value of x

We have,

x(x + 5) = $x^2+x+32$

After removing the brackets we get,

𝑥 × 𝑥 + 5𝑥 = $x^2+x+32$

⇒ $x^2$ + 5𝑥 = $x^2+x+32$

⇒ 5𝑥 − 𝑥 = $x^2-x^2+32$

⇒ 4𝑥 = 32

Now, transposing the term 4 to RHS we get,

⇒ 𝑥 = $\frac{32}{4}$

⇒ 𝑥 = 8

∴ The value of 𝑥 = 8.