Solve:
Add $3 a (a - b + c), 2 b (a - b + c)$

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Solution

$3 a (a - b + c) + 2 b (a - b + c)$
$= (3 a + 2 b) (a - b + c)$
$= 3 a^{2} - 3 a b + 3 a c + 2 a b - 2 b^{2} + 2 b c$
$= 3 a^{2} - a b - 2 b^{2} + 3 a c + 2 b c$

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