MyQuestionIcon

1

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Fundamental Theorem of Arithmetic

Solve: 3x +...

Question

Solve: $\frac{3 x + 2}{7} + \frac{4 (x + 1)}{5} = \frac{2}{3} (2 x + 1)$

Open in App

Solution

We have,

$\frac{3 x + 2}{7} + \frac{4 (x + 1)}{5} = \frac{2}{3} (2 x + 1)$

$\frac{5 (3 x + 2) + 28 (x + 1)}{5} = \frac{2}{3} (2 x + 1)$

$\frac{15 x + 10 + 28 x + 28}{5} = \frac{4 x + 2}{3}$

$\frac{43 x + 38}{5} = \frac{4 x + 2}{3}$

$129 x + 114 = 20 x + 10$

$109 x = - 104$

$x = - \frac{104}{109}$

Hence, the value of $x$ = $- \frac{104}{109}$ .

Suggest Corrections

thumbs-up

2

Similar questions

Q. Solve the inequation:

\frac{5 x + 1}{7} - 4 (x + \frac{2}{5}) \leq 1 \frac{3}{5} + \frac{3 x - 1}{7}, x \in R

Q. Solve the following equations.

3^{2 x + 1} = 3^{x + 2} + \sqrt{1 - {6.3}^{x} + 3^{2 (x + 1)}}

\frac{3 x + 5}{4 x + 2} = \frac{3 x + 4}{4 x + 7}

x

3^{(2 x + 4)} + 1 = 2 \times 3^{(x + 2)}

x

\frac{2}{3} (4 x - 1) - [4 x - \frac{1 - 3 x}{2}] = \frac{x - 7}{2}

.

View More

Join BYJU'S Learning Program

similar_icon

Related Videos

lock

Fundamental Theorem of Arithmetic

MATHEMATICS

Watch in App

explore_more_icon

Explore more

Fundamental Theorem of Arithmetic

Standard X Mathematics

Join BYJU'S Learning Program

CrossIcon