Solve- 8- -4-22-4-22-42-22

Given that, [ = 8×[ ( 6 ) #160; ^ 2 +( 2 ) #160; ^ 2 ] #160; 16+4 #160;; ...

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Standard XII

Mathematics

Integration Using Substitution

Solve: 8× [4...

Question

Solve:
$\frac{8 \times [(4 + 2)^{2} + (4 - 2)^{2}]}{(4)^{2} + (2)^{2}}$

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Solution

Given that
$\frac{8 \times [(4 + 2)^{2} + (4 - 2)^{2}]}{(4)^{2} + (2)^{2}}$
$= \frac{8 \times [{(6)}^{2} + {(2)}^{2}]}{16 + 4}$
$= \frac{8 \times 40}{20}$
$= \frac{320}{20}$
$= 16$

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Solve:8×[(4+2)2+(4−2)2](4)2+(2)2

Given that8×[(4+2)2+(4−2)2](4)2+(2)2=8×[(6)2+(2)2]16+4 =8×4020=32020=16

Solve:
$\frac{8 \times [(4 + 2)^{2} + (4 - 2)^{2}]}{(4)^{2} + (2)^{2}}$

Given that
$\frac{8 \times [(4 + 2)^{2} + (4 - 2)^{2}]}{(4)^{2} + (2)^{2}}$
$= \frac{8 \times [{(6)}^{2} + {(2)}^{2}]}{16 + 4}$
$= \frac{8 \times 40}{20}$
$= \frac{320}{20}$
$= 16$