If A(3,-4),B(4,5),C(5,-5),D(4,-10) are the vertices of a quadrilateral prove that ABCD is Rhombus?
Simplify: a−4 × b3 × c5 × d−7a−7 × b−3 × c2 × d−9
Solve for x: 6(x+5)–4(x+1)=9(x+3)