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Question

Solve: dydx+2y=sinx

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Solution

We have,

dydx+2y=sinx ……. (1)

Since, P=2,Q=sinx

Integrating factor,

I.F=ePdx

I.F=e2dx

I.F=e2x

Therefore, the general solution

y×I.F=Q×I.Fdx

y×e2x=sinx×e2xdx

We know that

eaxsinbxdx=eaxa2+b2(asinbxbcosbx)+C

Thus,

y×e2x=e2x22+12(2sinxcosx)+C

y×e2x=e2x5(2sinxcosx)+C

Hence, this is the answer.


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