wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Solve
dydx=sin1 x

Open in App
Solution

dydx=sin1x

dy=sin1xdx

dy=sin1xdx

y=sin1x1.dx[11x21.dx]

y=xsin1xx1x2.dx
Let t=1x2

2x.dx=dt

xdx=dt2
Now
y=xsin1xdt2t

y=xsin1x+dt2t

y=xsin1x+12t1/2.dt

y=xsin1x+12t1/2+112+1+c

y=xsin1x+12t1/21/2+c

y=xsin1x+t+c

y=xsin1x+1x2+c

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Definite Integral as Limit of Sum
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon