Question

Solve:

$\frac{(x+2)(x^2-2x+1)}{4+3x-x^2}\ge 0$

Answer 1

$\left(\frac{(x+2)(x-1{)}^2}{-(x^2-3x-4)}\right)\ge 0\left(\frac{(x+2)(x-1{)}^2}{(x-4)(x+1)}\right)\ge 0$

factors having even power doesn't change sign of the expression as

$(x-1{)}^{2}willbeeither+veor0\therefore x\in (-\infty ,-2]\cup (-1,4)$