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(x±a)(x±b) = x²±(a+b)x+ab.

Solve for : 9...

Question

Solve for : 9×(81)^x=1÷27^x-2

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Solution

9×81^x = 1/27^x-3

3²×3^4x = (1/3)^3(x-3)

3^2+4x = 3^-[3(x-3)]

Bases are equal. Exponents must be equal.

2+4x = -(3x-9)

2+4x = -3x+9

4x+3x = 9-2

7x = 7

x = 7/7

x = 1

Therefore, the value of x is 1

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(x±a)(x±b) = x²±(a+b)x+ab.

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