Solve for a: 3(a+4)+5(a+2)=14
-1
Given 3(a+4)+5(a+2)=14
⇒3a+12+5a+10=14 [Removing the brackets]
[rearranging the terms]
⇒3a+5a+12+10=14
⇒8a+22=14
⇒8a=14−22 [when +22 is transposed to RHS it becomes -22]
⇒8a=−8
[dividing both terms by 8]
8a8=a=−88=−1
⇒a=−1