Solve for $x$ :

$3 (9^{x}) < 8 (3^{x}) + 3$

(0,81)

No worries! We‘ve got your back. Try BYJU‘S free classes today!

$(- \infty, 1)$

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

$(- \infty, - 2) \cup (- 2, - 1) \cup (- 1, 0)$

No worries! We‘ve got your back. Try BYJU‘S free classes today!

None of these.

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is B
$(- \infty, 1)$

Put $3^{x} = t$ to obtain
$3 t^{2} - 8 t - 3 < 0 \Rightarrow (3 t + 1) (t - 3) < 0 A s 3 t + 1 > 0, w e g e t t < 3 o r x < 1$

Suggest Corrections

Similar questions

Solve for $x$ :

$3 (9^{x}) < 8 (3^{x}) + 3$

Solve for $x$ :

$3 (9^{x}) < 8 (3^{x}) + 3$

Solve for $x$ :

$3 (9^{x}) < 8 (3^{x}) + 3$

Solve for $x$

$2^{3 x} = 8^{3 x + 1}$

x + y = 8 3 x + 4 y = 25

Join BYJU'S Learning Program