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Liquids in Liquids

Solve for x 4...

Question

Solve for $x$

$4 x + 3 \geq 2 x + 17,$ $3 x - 5 < - 2.$

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Solution

Simplifying the given inequations separately

Now, $4 x + 3 \geq 2 x + 17$ (Given)

$\Rightarrow 2 x \geq 14$

$\Rightarrow x \geq 7$

Now, $3 x - 5 < - 2$ (Given)

$\Rightarrow 3 x < 3$

$\Rightarrow x < 1$

There is no common value of $x$ .

Hence, there is no solution.

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Similar questions

Solve the equations:

(i) 5x = 3x + 24;

(ii) 8t + 5 = 2t − 31;

(iii) 7x − 10 = 4x + 11;

(iv) 4z + 3 = 6 + 2z;

(v) 2x − 1 = 14 − x;

(vi) 6x + 1 = 3(x − 1) + 7;

(vii) ;

(viii) ;

(ix) 3(x + 1) = 12 + 4 (x − 1);

(x) 2x − 5 = 3(x − 5);

(xi) 6(1 − 4x) + 7(2 + 5x) = 53;

(xii) 3(x + 6) + 2 (x + 3) = 64;

(xiii) ;

(xiv) .

Q. Solve the system of inequalities:

4 x + 3 \geq 2 x + 17, 3 x - 5 < - 2

.

∣ ∣ ∣ ∣ \begin{matrix} 3 x + 4 & x + 2 & 2 x + 3 4 x + 5 & 2 x + 3 & 3 x + 4 10 x + 17 & 3 x + 5 & 5 x + 8 \end{matrix} ∣ ∣ ∣ ∣ = 0

. The value of the determinant at

x = - 1

Q. Solve the following equation for

x

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3 (2 x + 1) + 2 (3 x + 1) = 17

Q. Solve for x:

x = (2 x - \frac{3 x}{7}) - \frac{4 x - 27}{3} - 3

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Liquids in Liquids

Standard XII Chemistry

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