Question

Solve for X and y
$4x+\frac{y}{3}=\frac{8}{3}$
$\frac{x}{2}+3\frac{y}{4}=\frac{-5}{2}$
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Answer 1

4x + y/3 = 8/3 (1)
x/2 + 3y/4 = -5/2 (2)

Multipliy $\left(2\right)\times 8$

$\Rightarrow 4x+6y=-\mathrm{20........}\left(3\right)$

Subtract $\left(3\right)-\left(1\right)$

$6y-\frac{y}{3}=-20-\frac{8}{3}$
$\frac{17y}{3}=\frac{-68}{3}$
17y = -68
y = -4 ................... (4)

substitute (4) in (3)
$4x+6\times 4=-20$
$4x-24=-20$
$4x=-20+24$
$4x=4$
$x=1$

Hence, $x=1,y=-4$