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Solving Simultaneous Linear Equation Using Cramer's Rule

solve for x a...

Question

solve for x and y

a(x+y)+b(x-y)=a²-ab+b²

a(x+y)-b(x-y)=a²+ab+b²

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Solution

The above mentioned Method is the Actual Way of Doing it . If You read it once Again You will Understand

Firstly we are arranging the equation to take common out of x and y part

and then to solve the equation we are multiplying by a+b to first equation and by a-b to second equation so as to solve the equation (to make common terms)

from that solved part we get the value of x

and when we put the value of x in either one of the equation . we get the value of y. There is nowhere to be confused

The above mentioned is the best possible solution
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Similar questions

a (x + y) + b (x - y) = a^{2} - a b + b^{2}

a (x + y) - b (x - y) = a^{2} + a b + b^{2}

.

a (x + y) + b (x - y) = a^{2} - a b + b^{2}

a (x + y) - b (x - y) = a^{2} + a b + b^{2}

x

y

\frac{b x}{a} + \frac{a y}{b} = a^{2} + b^{2}

x + y = 2 a b

Q. Solve the equation for

x

y

\begin{matrix} (a - b) x + (a + b) y = a^{2} - 2 a b - b^{2} (a + b) (x + y) = a^{2} + b^{2} \end{matrix}

Q. solve for x and y
(a-b)x+(a+b)y=a2-2ab-b2
(a+b)(x+y)a2+b2

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