Question

Solve for x and $yx+\frac{6}{y}=6$ and $3x-\frac{8}{y}=5$

Answer 1

$yx+\left(\frac{6}{y}\right)=6and3x-\left(\frac{8}{y}\right)=5\therefore x=(5+(\frac{8}{y}\left)\right)\times \left(\frac{1}{3}\right)\therefore y\left(\frac{1}{3}\right)[5+(\frac{8}{y}\left)\right]+\left(\frac{6}{y}\right)=6\left(\frac{5y}{3}\right)+\left(\frac{8}{3}\right)+\left(\frac{6}{y}\right)=6\left(\frac{5y^2+8y+18}{3y}\right)=65y^2+8y+18=18y5y^2-10y+18=0norealsolution$