Question

Solve for $x$: $\frac{1}{5}(3x-2)-\frac{1}{3}(x+7)+1=0$.

• A. $144$
• B. $\frac{41}{4}$
• C. $124$
• D. $\frac{26}{4}$

Answer 1

The correct option is D $\frac{26}{4}$

Given, $\frac{1}{5}(3x-2)-\frac{1}{3}(x+7)+1=0$

Taking L.C.M., we get 15

$\Rightarrow 3(3x-2)-5(x+7)+15=0$

$\Rightarrow 9x-6-5x-35+15=0$

$\Rightarrow 4x=26$

$\Rightarrow x=\frac{26}{4}$