Solve For $x$ :
$l o g_{3} x - l o g_{3} 2 = 1$

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Solution

Logarithm equation :
$l o g_{3} x - l o g_{3} 2 = 1$
We need to solve for $x$
$l o g_{3} x = 1 + l o g_{3} 2$
Since, $1$ can be written as $l o g_{3} 3 = 1$
$\Rightarrow l o g_{3} x = \log_{3} 3 + l o g_{3} 2$
$\Rightarrow l o g_{3} x = \log_{3} (3 \times 2) \Rightarrow l o g_{3} x = \log_{3} 6$
$x = 6$
Hence, the value of $x$ is $6$ .

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