solve for 'x': (x^2- 6x+3) (x^2-6x -2)≥slant 50

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\frac{2 x - 2}{x^{2} - 36} - \frac{x - 2}{x^{2} - 6 x} = \frac{x - 1}{x^{2} + 6 x}

\int \frac{x - 3}{x^{2} - 6 x + 17} d x

x^{2} + 2 \sqrt{x^{2} + 6 x} = 24 - 6 x

f (x) = \frac{x^{2} + x - 6}{x^{2} - 6 x + 8}

f (x) = 3

{log}_{5 - x} (x^{2} - 6 x + 65) = 2

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