Question

Solve:
(i) $-96÷16$
(ii) $98÷-28$
(iii) $-51÷68$
(iv) $38÷-57$
(v) $-85÷20$
(vi) $-150÷-25$
(vii) $100÷60$
(viii) $9÷-54$
(ix) $78÷65$
(x) $-5÷-315$

Answer 1

(i) $-96÷16=\frac{-96}{16}=\frac{(-6)\times 16}{16}=-6$ [$\because -96=16\times 6$]

(ii) $98÷-28=\frac{98}{-28}=\frac{\left(7\right)\times 14}{(-14)\left(2\right)}=\frac{-7}{2}$

(iii) $-51÷68=\frac{-51}{68}=\frac{\left(17\right)\times (-3)}{17\times 4}=\frac{-3}{4}$

(iv) $38÷-57=\frac{38}{-57}=\frac{19\times 2}{(-19)\times 3}=\frac{-2}{3}$

(v) $-85÷20=\frac{-85}{20}=\frac{(-17)\times 5}{5\times 4}=\frac{-17}{4}$

(vi) $-150÷-25=\frac{-150}{-25}=\frac{(-25)\times 6}{-25}=6$ [$\because 150=25\times 6$]

(vii) $100÷60=\frac{100}{60}=\frac{20\times 5}{20\times 3}=\frac{5}{3}$

(viii) $9÷-54=\frac{9}{-54}=\frac{9}{(-6)\times 6}=\frac{-1}{6}$

(ix) $78÷65=\frac{78}{65}=\frac{13\times 6}{13\times 5}=\frac{6}{5}$

(x) $-5÷-315=\frac{-5}{-315}=\frac{(-5)}{(-5)\times \left(63\right)}=\frac{1}{63}$