We have,
(4a+36)2−(4a−36)2+48ab
=(4a+36)2−(4a−36)2+48ab
=(4a)2+(36)2+2×4a×36−[(4a)2+(36)2−2×4a×36]+48ab
=(4a)2+(36)2+2×4a×36−(4a)2−(36)2+2×4a×36+48ab
=288a+288a+48ab
=576a+48ab
=48a(12+b)
Hence, the answer is 48a(12+b).
(4a+3b)² -(4a-3b)²+48ab
Solve 362−352= ___